Integrand size = 24, antiderivative size = 235 \[ \int x^2 \left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2} \, dx=\frac {c^2 \left (16 a^2 d^2+3 b c (b c-4 a d)\right ) x \sqrt {c+d x^2}}{256 d^3}+\frac {c \left (16 a^2 d^2+3 b c (b c-4 a d)\right ) x^3 \sqrt {c+d x^2}}{128 d^2}+\frac {\left (16 a^2 d^2+3 b c (b c-4 a d)\right ) x^3 \left (c+d x^2\right )^{3/2}}{96 d^2}-\frac {b (b c-4 a d) x^3 \left (c+d x^2\right )^{5/2}}{16 d^2}+\frac {b^2 x^5 \left (c+d x^2\right )^{5/2}}{10 d}-\frac {c^3 \left (16 a^2 d^2+3 b c (b c-4 a d)\right ) \text {arctanh}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{256 d^{7/2}} \]
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Time = 0.15 (sec) , antiderivative size = 232, normalized size of antiderivative = 0.99, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {475, 470, 285, 327, 223, 212} \[ \int x^2 \left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2} \, dx=-\frac {c^3 \left (16 a^2 d^2+3 b c (b c-4 a d)\right ) \text {arctanh}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{256 d^{7/2}}+\frac {c^2 x \sqrt {c+d x^2} \left (16 a^2 d^2+3 b c (b c-4 a d)\right )}{256 d^3}+\frac {1}{96} x^3 \left (c+d x^2\right )^{3/2} \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right )+\frac {c x^3 \sqrt {c+d x^2} \left (16 a^2 d^2+3 b c (b c-4 a d)\right )}{128 d^2}-\frac {b x^3 \left (c+d x^2\right )^{5/2} (b c-4 a d)}{16 d^2}+\frac {b^2 x^5 \left (c+d x^2\right )^{5/2}}{10 d} \]
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Rule 212
Rule 223
Rule 285
Rule 327
Rule 470
Rule 475
Rubi steps \begin{align*} \text {integral}& = \frac {b^2 x^5 \left (c+d x^2\right )^{5/2}}{10 d}+\frac {\int x^2 \left (c+d x^2\right )^{3/2} \left (10 a^2 d-5 b (b c-4 a d) x^2\right ) \, dx}{10 d} \\ & = -\frac {b (b c-4 a d) x^3 \left (c+d x^2\right )^{5/2}}{16 d^2}+\frac {b^2 x^5 \left (c+d x^2\right )^{5/2}}{10 d}+\frac {1}{16} \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) \int x^2 \left (c+d x^2\right )^{3/2} \, dx \\ & = \frac {1}{96} \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x^3 \left (c+d x^2\right )^{3/2}-\frac {b (b c-4 a d) x^3 \left (c+d x^2\right )^{5/2}}{16 d^2}+\frac {b^2 x^5 \left (c+d x^2\right )^{5/2}}{10 d}+\frac {1}{32} \left (c \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right )\right ) \int x^2 \sqrt {c+d x^2} \, dx \\ & = \frac {1}{128} c \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x^3 \sqrt {c+d x^2}+\frac {1}{96} \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x^3 \left (c+d x^2\right )^{3/2}-\frac {b (b c-4 a d) x^3 \left (c+d x^2\right )^{5/2}}{16 d^2}+\frac {b^2 x^5 \left (c+d x^2\right )^{5/2}}{10 d}+\frac {1}{128} \left (c^2 \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right )\right ) \int \frac {x^2}{\sqrt {c+d x^2}} \, dx \\ & = \frac {c^2 \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x \sqrt {c+d x^2}}{256 d}+\frac {1}{128} c \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x^3 \sqrt {c+d x^2}+\frac {1}{96} \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x^3 \left (c+d x^2\right )^{3/2}-\frac {b (b c-4 a d) x^3 \left (c+d x^2\right )^{5/2}}{16 d^2}+\frac {b^2 x^5 \left (c+d x^2\right )^{5/2}}{10 d}-\frac {\left (c^3 \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right )\right ) \int \frac {1}{\sqrt {c+d x^2}} \, dx}{256 d} \\ & = \frac {c^2 \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x \sqrt {c+d x^2}}{256 d}+\frac {1}{128} c \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x^3 \sqrt {c+d x^2}+\frac {1}{96} \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x^3 \left (c+d x^2\right )^{3/2}-\frac {b (b c-4 a d) x^3 \left (c+d x^2\right )^{5/2}}{16 d^2}+\frac {b^2 x^5 \left (c+d x^2\right )^{5/2}}{10 d}-\frac {\left (c^3 \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right )\right ) \text {Subst}\left (\int \frac {1}{1-d x^2} \, dx,x,\frac {x}{\sqrt {c+d x^2}}\right )}{256 d} \\ & = \frac {c^2 \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x \sqrt {c+d x^2}}{256 d}+\frac {1}{128} c \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x^3 \sqrt {c+d x^2}+\frac {1}{96} \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) x^3 \left (c+d x^2\right )^{3/2}-\frac {b (b c-4 a d) x^3 \left (c+d x^2\right )^{5/2}}{16 d^2}+\frac {b^2 x^5 \left (c+d x^2\right )^{5/2}}{10 d}-\frac {c^3 \left (16 a^2+\frac {3 b c (b c-4 a d)}{d^2}\right ) \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{256 d^{3/2}} \\ \end{align*}
Time = 0.81 (sec) , antiderivative size = 200, normalized size of antiderivative = 0.85 \[ \int x^2 \left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2} \, dx=\frac {\sqrt {d} x \sqrt {c+d x^2} \left (80 a^2 d^2 \left (3 c^2+14 c d x^2+8 d^2 x^4\right )+60 a b d \left (-3 c^3+2 c^2 d x^2+24 c d^2 x^4+16 d^3 x^6\right )+3 b^2 \left (15 c^4-10 c^3 d x^2+8 c^2 d^2 x^4+176 c d^3 x^6+128 d^4 x^8\right )\right )+30 c^3 \left (3 b^2 c^2-12 a b c d+16 a^2 d^2\right ) \text {arctanh}\left (\frac {\sqrt {d} x}{\sqrt {c}-\sqrt {c+d x^2}}\right )}{3840 d^{7/2}} \]
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Time = 2.98 (sec) , antiderivative size = 173, normalized size of antiderivative = 0.74
method | result | size |
pseudoelliptic | \(\frac {\left (-a^{2} c^{3} d^{2}+\frac {3}{4} a b \,c^{4} d -\frac {3}{16} b^{2} c^{5}\right ) \operatorname {arctanh}\left (\frac {\sqrt {d \,x^{2}+c}}{x \sqrt {d}}\right )+x \left (c^{2} \left (\frac {1}{10} b^{2} x^{4}+\frac {1}{2} a b \,x^{2}+a^{2}\right ) d^{\frac {5}{2}}+\frac {14 x^{2} \left (\frac {33}{70} b^{2} x^{4}+\frac {9}{7} a b \,x^{2}+a^{2}\right ) c \,d^{\frac {7}{2}}}{3}+\left (\frac {8}{5} b^{2} x^{8}+4 a b \,x^{6}+\frac {8}{3} a^{2} x^{4}\right ) d^{\frac {9}{2}}-\frac {3 b \left (\left (\frac {b \,x^{2}}{6}+a \right ) d^{\frac {3}{2}}-\frac {b \sqrt {d}\, c}{4}\right ) c^{3}}{4}\right ) \sqrt {d \,x^{2}+c}}{16 d^{\frac {7}{2}}}\) | \(173\) |
risch | \(\frac {x \left (384 b^{2} x^{8} d^{4}+960 a b \,d^{4} x^{6}+528 b^{2} c \,d^{3} x^{6}+640 a^{2} d^{4} x^{4}+1440 c a b \,x^{4} d^{3}+24 b^{2} c^{2} d^{2} x^{4}+1120 a^{2} c \,d^{3} x^{2}+120 a b \,c^{2} d^{2} x^{2}-30 b^{2} c^{3} d \,x^{2}+240 a^{2} c^{2} d^{2}-180 a b \,c^{3} d +45 b^{2} c^{4}\right ) \sqrt {d \,x^{2}+c}}{3840 d^{3}}-\frac {c^{3} \left (16 a^{2} d^{2}-12 a b c d +3 b^{2} c^{2}\right ) \ln \left (x \sqrt {d}+\sqrt {d \,x^{2}+c}\right )}{256 d^{\frac {7}{2}}}\) | \(198\) |
default | \(b^{2} \left (\frac {x^{5} \left (d \,x^{2}+c \right )^{\frac {5}{2}}}{10 d}-\frac {c \left (\frac {x^{3} \left (d \,x^{2}+c \right )^{\frac {5}{2}}}{8 d}-\frac {3 c \left (\frac {x \left (d \,x^{2}+c \right )^{\frac {5}{2}}}{6 d}-\frac {c \left (\frac {x \left (d \,x^{2}+c \right )^{\frac {3}{2}}}{4}+\frac {3 c \left (\frac {x \sqrt {d \,x^{2}+c}}{2}+\frac {c \ln \left (x \sqrt {d}+\sqrt {d \,x^{2}+c}\right )}{2 \sqrt {d}}\right )}{4}\right )}{6 d}\right )}{8 d}\right )}{2 d}\right )+a^{2} \left (\frac {x \left (d \,x^{2}+c \right )^{\frac {5}{2}}}{6 d}-\frac {c \left (\frac {x \left (d \,x^{2}+c \right )^{\frac {3}{2}}}{4}+\frac {3 c \left (\frac {x \sqrt {d \,x^{2}+c}}{2}+\frac {c \ln \left (x \sqrt {d}+\sqrt {d \,x^{2}+c}\right )}{2 \sqrt {d}}\right )}{4}\right )}{6 d}\right )+2 a b \left (\frac {x^{3} \left (d \,x^{2}+c \right )^{\frac {5}{2}}}{8 d}-\frac {3 c \left (\frac {x \left (d \,x^{2}+c \right )^{\frac {5}{2}}}{6 d}-\frac {c \left (\frac {x \left (d \,x^{2}+c \right )^{\frac {3}{2}}}{4}+\frac {3 c \left (\frac {x \sqrt {d \,x^{2}+c}}{2}+\frac {c \ln \left (x \sqrt {d}+\sqrt {d \,x^{2}+c}\right )}{2 \sqrt {d}}\right )}{4}\right )}{6 d}\right )}{8 d}\right )\) | \(305\) |
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Time = 0.33 (sec) , antiderivative size = 419, normalized size of antiderivative = 1.78 \[ \int x^2 \left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2} \, dx=\left [\frac {15 \, {\left (3 \, b^{2} c^{5} - 12 \, a b c^{4} d + 16 \, a^{2} c^{3} d^{2}\right )} \sqrt {d} \log \left (-2 \, d x^{2} + 2 \, \sqrt {d x^{2} + c} \sqrt {d} x - c\right ) + 2 \, {\left (384 \, b^{2} d^{5} x^{9} + 48 \, {\left (11 \, b^{2} c d^{4} + 20 \, a b d^{5}\right )} x^{7} + 8 \, {\left (3 \, b^{2} c^{2} d^{3} + 180 \, a b c d^{4} + 80 \, a^{2} d^{5}\right )} x^{5} - 10 \, {\left (3 \, b^{2} c^{3} d^{2} - 12 \, a b c^{2} d^{3} - 112 \, a^{2} c d^{4}\right )} x^{3} + 15 \, {\left (3 \, b^{2} c^{4} d - 12 \, a b c^{3} d^{2} + 16 \, a^{2} c^{2} d^{3}\right )} x\right )} \sqrt {d x^{2} + c}}{7680 \, d^{4}}, \frac {15 \, {\left (3 \, b^{2} c^{5} - 12 \, a b c^{4} d + 16 \, a^{2} c^{3} d^{2}\right )} \sqrt {-d} \arctan \left (\frac {\sqrt {-d} x}{\sqrt {d x^{2} + c}}\right ) + {\left (384 \, b^{2} d^{5} x^{9} + 48 \, {\left (11 \, b^{2} c d^{4} + 20 \, a b d^{5}\right )} x^{7} + 8 \, {\left (3 \, b^{2} c^{2} d^{3} + 180 \, a b c d^{4} + 80 \, a^{2} d^{5}\right )} x^{5} - 10 \, {\left (3 \, b^{2} c^{3} d^{2} - 12 \, a b c^{2} d^{3} - 112 \, a^{2} c d^{4}\right )} x^{3} + 15 \, {\left (3 \, b^{2} c^{4} d - 12 \, a b c^{3} d^{2} + 16 \, a^{2} c^{2} d^{3}\right )} x\right )} \sqrt {d x^{2} + c}}{3840 \, d^{4}}\right ] \]
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Time = 0.45 (sec) , antiderivative size = 432, normalized size of antiderivative = 1.84 \[ \int x^2 \left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2} \, dx=\begin {cases} - \frac {c \left (a^{2} c^{2} - \frac {3 c \left (2 a^{2} c d + 2 a b c^{2} - \frac {5 c \left (a^{2} d^{2} + 4 a b c d + b^{2} c^{2} - \frac {7 c \left (2 a b d^{2} + \frac {11 b^{2} c d}{10}\right )}{8 d}\right )}{6 d}\right )}{4 d}\right ) \left (\begin {cases} \frac {\log {\left (2 \sqrt {d} \sqrt {c + d x^{2}} + 2 d x \right )}}{\sqrt {d}} & \text {for}\: c \neq 0 \\\frac {x \log {\left (x \right )}}{\sqrt {d x^{2}}} & \text {otherwise} \end {cases}\right )}{2 d} + \sqrt {c + d x^{2}} \left (\frac {b^{2} d x^{9}}{10} + \frac {x^{7} \cdot \left (2 a b d^{2} + \frac {11 b^{2} c d}{10}\right )}{8 d} + \frac {x^{5} \left (a^{2} d^{2} + 4 a b c d + b^{2} c^{2} - \frac {7 c \left (2 a b d^{2} + \frac {11 b^{2} c d}{10}\right )}{8 d}\right )}{6 d} + \frac {x^{3} \cdot \left (2 a^{2} c d + 2 a b c^{2} - \frac {5 c \left (a^{2} d^{2} + 4 a b c d + b^{2} c^{2} - \frac {7 c \left (2 a b d^{2} + \frac {11 b^{2} c d}{10}\right )}{8 d}\right )}{6 d}\right )}{4 d} + \frac {x \left (a^{2} c^{2} - \frac {3 c \left (2 a^{2} c d + 2 a b c^{2} - \frac {5 c \left (a^{2} d^{2} + 4 a b c d + b^{2} c^{2} - \frac {7 c \left (2 a b d^{2} + \frac {11 b^{2} c d}{10}\right )}{8 d}\right )}{6 d}\right )}{4 d}\right )}{2 d}\right ) & \text {for}\: d \neq 0 \\c^{\frac {3}{2}} \left (\frac {a^{2} x^{3}}{3} + \frac {2 a b x^{5}}{5} + \frac {b^{2} x^{7}}{7}\right ) & \text {otherwise} \end {cases} \]
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Time = 0.21 (sec) , antiderivative size = 299, normalized size of antiderivative = 1.27 \[ \int x^2 \left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2} \, dx=\frac {{\left (d x^{2} + c\right )}^{\frac {5}{2}} b^{2} x^{5}}{10 \, d} - \frac {{\left (d x^{2} + c\right )}^{\frac {5}{2}} b^{2} c x^{3}}{16 \, d^{2}} + \frac {{\left (d x^{2} + c\right )}^{\frac {5}{2}} a b x^{3}}{4 \, d} + \frac {{\left (d x^{2} + c\right )}^{\frac {5}{2}} b^{2} c^{2} x}{32 \, d^{3}} - \frac {{\left (d x^{2} + c\right )}^{\frac {3}{2}} b^{2} c^{3} x}{128 \, d^{3}} - \frac {3 \, \sqrt {d x^{2} + c} b^{2} c^{4} x}{256 \, d^{3}} - \frac {{\left (d x^{2} + c\right )}^{\frac {5}{2}} a b c x}{8 \, d^{2}} + \frac {{\left (d x^{2} + c\right )}^{\frac {3}{2}} a b c^{2} x}{32 \, d^{2}} + \frac {3 \, \sqrt {d x^{2} + c} a b c^{3} x}{64 \, d^{2}} + \frac {{\left (d x^{2} + c\right )}^{\frac {5}{2}} a^{2} x}{6 \, d} - \frac {{\left (d x^{2} + c\right )}^{\frac {3}{2}} a^{2} c x}{24 \, d} - \frac {\sqrt {d x^{2} + c} a^{2} c^{2} x}{16 \, d} - \frac {3 \, b^{2} c^{5} \operatorname {arsinh}\left (\frac {d x}{\sqrt {c d}}\right )}{256 \, d^{\frac {7}{2}}} + \frac {3 \, a b c^{4} \operatorname {arsinh}\left (\frac {d x}{\sqrt {c d}}\right )}{64 \, d^{\frac {5}{2}}} - \frac {a^{2} c^{3} \operatorname {arsinh}\left (\frac {d x}{\sqrt {c d}}\right )}{16 \, d^{\frac {3}{2}}} \]
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Time = 0.30 (sec) , antiderivative size = 219, normalized size of antiderivative = 0.93 \[ \int x^2 \left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2} \, dx=\frac {1}{3840} \, {\left (2 \, {\left (4 \, {\left (6 \, {\left (8 \, b^{2} d x^{2} + \frac {11 \, b^{2} c d^{8} + 20 \, a b d^{9}}{d^{8}}\right )} x^{2} + \frac {3 \, b^{2} c^{2} d^{7} + 180 \, a b c d^{8} + 80 \, a^{2} d^{9}}{d^{8}}\right )} x^{2} - \frac {5 \, {\left (3 \, b^{2} c^{3} d^{6} - 12 \, a b c^{2} d^{7} - 112 \, a^{2} c d^{8}\right )}}{d^{8}}\right )} x^{2} + \frac {15 \, {\left (3 \, b^{2} c^{4} d^{5} - 12 \, a b c^{3} d^{6} + 16 \, a^{2} c^{2} d^{7}\right )}}{d^{8}}\right )} \sqrt {d x^{2} + c} x + \frac {{\left (3 \, b^{2} c^{5} - 12 \, a b c^{4} d + 16 \, a^{2} c^{3} d^{2}\right )} \log \left ({\left | -\sqrt {d} x + \sqrt {d x^{2} + c} \right |}\right )}{256 \, d^{\frac {7}{2}}} \]
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Timed out. \[ \int x^2 \left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2} \, dx=\int x^2\,{\left (b\,x^2+a\right )}^2\,{\left (d\,x^2+c\right )}^{3/2} \,d x \]
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